Asked by Nicole
What mass of KBr is required to prepare 8.oo L of .400 M solution?
Answers
Answered by
DrBob222
How many mols do you need? That's M x L = 0.400 M x 8.00 L = ?
Then mols KBr = grams KBr/molar mass KBr.
Then mols KBr = grams KBr/molar mass KBr.
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