Question
What mass of H2O is required to form 1.2 L of O2 at a temperature of 310 K and a pressure of 0.950 atm?
2H2O (l) ---> 2H (g) + O2 (g)
2H2O (l) ---> 2H (g) + O2 (g)
Answers
DrBob222
I have corrected the equation.
2H2O(l) ---> 2H2 (g) + O2 (g)
Use PV = nRT to convert 1.2 L of O2 at the conditions listed to moles. Solve for n.
Using the coefficients in the balanced equation, convert moles of O2 to moles H2O.
Convert moles H2O to grams. g = moles x molar mass.
2H2O(l) ---> 2H2 (g) + O2 (g)
Use PV = nRT to convert 1.2 L of O2 at the conditions listed to moles. Solve for n.
Using the coefficients in the balanced equation, convert moles of O2 to moles H2O.
Convert moles H2O to grams. g = moles x molar mass.