Asked by Anonymous
Find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.
Answers
Answered by
Steve
Let the 3 numbers be
x-2,x,x+2
(x-2)*x = (x+2)^2 - 34
x=5
So, the numbers are 3,5,7
x-2,x,x+2
(x-2)*x = (x+2)^2 - 34
x=5
So, the numbers are 3,5,7
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