Asked by Estefani
Find two consecutive numbers who squares differ by 31 I got 2 and 31 but I got it wrong someone help me please
Answers
Answered by
Reiny
consecutive number are one apart
so let the first be x
then the 2nd is x+1
their squares differ by 1 ---> (x+1)^ - x^2 = 31
x^2 + 2x + 1 - x^2 = 31
2x = 30
x = 15
so the first is 15, the next one is 16
check:
16^2 - 15^2
= 256 - 225
= 31
all is good!
so let the first be x
then the 2nd is x+1
their squares differ by 1 ---> (x+1)^ - x^2 = 31
x^2 + 2x + 1 - x^2 = 31
2x = 30
x = 15
so the first is 15, the next one is 16
check:
16^2 - 15^2
= 256 - 225
= 31
all is good!
Answered by
Jesse Wellens
Write an inequality for the statement:The average temperature in January was 11° C which is warmer than Decembers average temperature of -1° C.
Answered by
James
We know in January it was 11 degrees Celsius
In December it is -1 degree Celsius
Take that and put -1 on the left.
Now put a < sign next to the one.
After that put the 11 next to the < sign.Now you have your inequality of -1<11.
In December it is -1 degree Celsius
Take that and put -1 on the left.
Now put a < sign next to the one.
After that put the 11 next to the < sign.Now you have your inequality of -1<11.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.