Asked by Mark conlon
What are 9 consecutive numbers that equal 2002
Answers
Answered by
oobleck
You want x + (x+1) + ... (x+8) = 2002
9x + (1+2+3+...+8) = 20002
9x + 8*9/2 = 2002
...
9x + (1+2+3+...+8) = 20002
9x + 8*9/2 = 2002
...
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