Asked by Tuurky

Two consecutive numbers are such that five times the smaller one exceeds twice the greater by 16. Find the numbers
Answered by oobleck
let the numbers be x and x+1. Then we know that
x = 2(x+1) + 16
Answered by Elly
I can't really understand the answer
Answered by Doreen
I need the answer
Answered by USHER
Let the numbers be a, a+1
5a = 2(a+1)+16
5a = 2a+ 2+16
5a-2a = 18
3a/3 = 18/3
a = 6
= 6 and 7
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