Asked by Anonymous
How many liters of nitric acid are needed to neutralize 25mL of 4.2M calcium hydroxide?
Answers
Answered by
bonjo
the reaction is:
2HNO3 + Ca(OH)2 --> Ca(NO3)2 + 2H2O
we know the mole of calcium hydroxide
n=cv = 4.2mol/L x 0.025L = _____
this mole needs to be neutralized by the acid. so we need to calculate the mole of nitric acid using the mole ratio from the balanced equation;
2 mole of nitric acid neutralize 1 mole of calcium hydroxide.
2:1
x:____(the mole of calcium hydroxide)
where x is the mole of nitric acid. use that mole to calculate the volume..can you???..we need a concentration of nitric acid...is there a concentration for nitric acid??? check again..
2HNO3 + Ca(OH)2 --> Ca(NO3)2 + 2H2O
we know the mole of calcium hydroxide
n=cv = 4.2mol/L x 0.025L = _____
this mole needs to be neutralized by the acid. so we need to calculate the mole of nitric acid using the mole ratio from the balanced equation;
2 mole of nitric acid neutralize 1 mole of calcium hydroxide.
2:1
x:____(the mole of calcium hydroxide)
where x is the mole of nitric acid. use that mole to calculate the volume..can you???..we need a concentration of nitric acid...is there a concentration for nitric acid??? check again..
Answered by
asssu
41ml
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.