Asked by Brett
1. Nitric acid is produced via the following equation: 3 NO2 + H2O = 2HNO3 + NO. How many grams of NO2 are required to produce 7.5 grams of HNO3?
Answers
Answered by
Barry
Dear Brett,
molar mass of the HNO3= 1+14+16x3
=63
number of moles of the HNO3 produced in the reaction = 7.5/63
= 0.119
According to the equation provided 3 moles of NO2 will produce 2 moles of HNO3
Thus,number of moles of NO2 required=
0.119/2x3
= 0.179
mass of N02 required=
0.179x(14+32)
= 8.214g
Therefore, 8.214 grams of N02 is required
Hope it helps:)
molar mass of the HNO3= 1+14+16x3
=63
number of moles of the HNO3 produced in the reaction = 7.5/63
= 0.119
According to the equation provided 3 moles of NO2 will produce 2 moles of HNO3
Thus,number of moles of NO2 required=
0.119/2x3
= 0.179
mass of N02 required=
0.179x(14+32)
= 8.214g
Therefore, 8.214 grams of N02 is required
Hope it helps:)
Answered by
Stef
The answer should be 8.24 not 8.214
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