Asked by Therese

If 30.0 mL of 0.2 M nitric acid and 30.0 mL of 0.25 M solution of sodium hydroxide are mixed, what is the molarity of sodium nitrate? Assume that total volume of the solution after mixing is equal 60.0 mL.

Answers

Answered by Devron
HNO3 + NaOH---> H2O + NaNO3

Nitric acid is the limiting reagent.


Molarity=moles of sodium nitrate/60 x 10^-3L=(30 x 10^-3L *0.2M)/60 x 10^-3L
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions