The perimeter of a rectangle is 94 ft, and the area of the rectangle is 90ft ^2. What are the dimensions of the rectangle?

Answer 1

2p+2l = 94
p+l = 47
l = 47-p

pl = 90
p(47-p) = 90
-p^2 + 47p - 90 = 0
p^2 - 47p + 90 = 0
(p-45)(p-2) = 0

p = 45 or p = 2

if p=45 , l = 47-45 = 2
if p = 2, l = 47-2 = 45

the rectangle is 2 ft by 45 ft