Asked by topaz
The perimeter of a rectangle is 94 ft, and the area of the rectangle is 90ft ^2. What are the dimensions of the rectangle?
Answers
Answered by
Reiny
2p+2l = 94
p+l = 47
l = 47-p
pl = 90
p(47-p) = 90
-p^2 + 47p - 90 = 0
p^2 - 47p + 90 = 0
(p-45)(p-2) = 0
p = 45 or p = 2
if p=45 , l = 47-45 = 2
if p = 2, l = 47-2 = 45
the rectangle is 2 ft by 45 ft
p+l = 47
l = 47-p
pl = 90
p(47-p) = 90
-p^2 + 47p - 90 = 0
p^2 - 47p + 90 = 0
(p-45)(p-2) = 0
p = 45 or p = 2
if p=45 , l = 47-45 = 2
if p = 2, l = 47-2 = 45
the rectangle is 2 ft by 45 ft
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