Asked by barco

You have 333 mL of alkaline solution at pH = 11.1. You wish to neutralize this by reacting it with 222 mL of acid. What must be the value of the pH of the acid?
Answered by barco
just use the formula pH + pOH = 14.0 where pH is unknown and pOH is currently the pH given in the question because, it is a weak base.
Answered by anonyms
Answer please...
Answered by himani.
thank u
answer is 2.9
Answered by DrBob222
I do not believe the answer is 2.9. It should be 2.9 ONLY if the volume of the base = volume of acid but it isn't. The acid is stronger than the base (222 mL vs 333 mL); therefore, the acid should be slightly lower in pH than 2.9. My calculator says 2.7.
Answered by anonyms
2.9 is correct. pH = 14-11.1= 2.9
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