When 3.54 g of a nonelectrolyte solute is dissolved in 675 mL of water at 24 °C, the resulting solution exerts an osmotic pressure of 913 torr.

3 answers

Do you have a question?
What is molar concentration of solution?

how many moles of solute are in solution?

What is the molar mass of solute?
pi = MRT
pi is osmotic pressure in atm.
M is molarity
R = 0.99206
T = 24 C converted to kelvin.

Then M = mol/L. You know L and M, solve for mols.

Then mols = grams/molar mass
You know mols and grams, solve for molar mass.