Asked by LLamaboy
When 3.10 g of a nonelectrolyte solute is dissolved in water to make 755 mL of solution at 26 °C, the solution exerts an osmotic pressure of 821 torr.
What is the molar concentration of the solution?
How many moles of solute are in the solution?
What is the molar mass of the solute?
What is the molar concentration of the solution?
How many moles of solute are in the solution?
What is the molar mass of the solute?
Answers
Answered by
DrBob222
pi = nRT
pi = 821/760
Substitute R and T (remember T must be in kelvin) and solve for n.
Then n = grams/molar mass. You know n and grams, solve for molar mass.
M = mols/L solution.
pi = 821/760
Substitute R and T (remember T must be in kelvin) and solve for n.
Then n = grams/molar mass. You know n and grams, solve for molar mass.
M = mols/L solution.
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