Asked by Tsomo
When 3.15 g of a nonelectrolyte solute is dissolved in water to make 135 mL of solution at 21 °C, the solution exerts an osmotic pressure of 869 torr.
What is the molar mass of the solute?
What is the molar concentration of the solution?
How many moles of solute are in the solution?
What is the molar mass of the solute?
What is the molar concentration of the solution?
How many moles of solute are in the solution?
Answers
Answered by
DrBob222
pi = MRT
pi = 869/760 = ?
M solve for this
R = 0.08205 L*atm/mol*k
T = 273 + 21 = ?
M gives you part b.
Then M = mols/L solution, you know L solution and M, solve for mols and that is part c.
Part a is mol = grams/molar mass. You know grams and mols, solve for molar mass.
pi = 869/760 = ?
M solve for this
R = 0.08205 L*atm/mol*k
T = 273 + 21 = ?
M gives you part b.
Then M = mols/L solution, you know L solution and M, solve for mols and that is part c.
Part a is mol = grams/molar mass. You know grams and mols, solve for molar mass.
Answered by
fkthis
*insert middle finger*
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.