Question
If something originally contained 32.0 g of Po-210, which has a half-life of 10.5 minutes, and was now 73.5 minutes old, how many grams would be left?
Answers
bobpursley
two ways:
amount left=32*(1/2)^(73.5/10.5)
put this in your google search window:
32*(1/2)^(73.5/10.5)=
0r this way:
amount left=32*e^(-.693*73.5/10.5)
put this in your google search window:
32*e^(-.693* 73.5/10.5)=
amount left=32*(1/2)^(73.5/10.5)
put this in your google search window:
32*(1/2)^(73.5/10.5)=
0r this way:
amount left=32*e^(-.693*73.5/10.5)
put this in your google search window:
32*e^(-.693* 73.5/10.5)=