Asked by Claire

Find the area of the region between the curve y^2=4x and the line x=3.
Answered by bobpursley
ok, sketch it.

area=INT2ydx from x=0 to 3

area=INT 2*sqrt(4x) dx
= INT 2*2sqrtx dx from x=0 to x^3

= 4*2/3 x^3 over limits
= 8/3 *27

check my work
Answered by Claire
I sorry but I don't undestand. What would be f(x) and g(x)?
Answered by bobpursley
I have no idea what you mean by F(x) or g(x).
Answered by Prue
I'm sorry. For the equation that I have to use for this it is:

Integral symbol(f(x)-g(x))dx
Answered by Prue
Sorry I posted into the wrong conversation, please ignore me. Thank you.
Answered by bobpursley
f(x)=sqrt(4x) g(x)=-sqrt(4x)

f(x)-g(x)=2*f(x)
Answered by Claire
Why is g(x)=-sqrt(4x)?
Answered by bobpursley
sketch it!

sqrt4x=+- 2sqrtx
Answered by Claire
Oh I forgot about the ± sign. THANK YOU!!
There are no AI answers yet. The ability to request AI answers is coming soon!