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find the area of the region bounded by y=1-2x^2 and y=|x|
4 years ago

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oobleck
the region is symmetric, and the curves intersect at (1,1)
a = 2∫[0,1] (2-x^2)-x dx = 7/3
4 years ago
oobleck
or, using horizontal strips of width dy, you need to switch curves at (1,1)
a = 2(∫[0,1] y dy + ∫[1,2] √(2-y) dy) = 2(1/2 + 2/3) = 7/3
4 years ago

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