Asked by Audrey

Solve the equation
log[1/6](x^2+x)-log[1/6](x^2-x)=-2
Answered by Steve
raise 1/6 to the power

(x^2+x)/(x^2-x) = (1/6)^-2 = 36
(x+1)/(x-1) = 36
x = 37/35