Asked by Claire
Solve this equation:
5^2x+1 + 24(5^x) = 5
The answer has to be -1 but I can't understand how to get this answer. Can someone please explain? Thanks!
5^2x+1 + 24(5^x) = 5
The answer has to be -1 but I can't understand how to get this answer. Can someone please explain? Thanks!
Answers
Answered by
bobpursley
let z= 5^x then
5z^2 + 24z -5=0
using quadratic equation
z= -24 +- sqrt 24^2+100 /10
z= -24 +- 26 /10
z= 1/5; z= -5
5^x= 1/5 >>> x=-1
or5^x= -5 >>> no possible x
5z^2 + 24z -5=0
using quadratic equation
z= -24 +- sqrt 24^2+100 /10
z= -24 +- 26 /10
z= 1/5; z= -5
5^x= 1/5 >>> x=-1
or5^x= -5 >>> no possible x
Answered by
Claire
Thanks! But how did you substitute 5z^2 for 5^2x+1?
Answered by
bobpursley
5^(2x+1)= 5^1 * 5^2x= 5*5^2x= 5z^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.