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The built-in composite bar BC of length L=2 m is composed of two materials with equal cross sectional area A = 100 mm2. The fir...Asked by SAFEWAY
The built-in composite bar BC of length L=2 m is composed of two materials with equal cross sectional area A = 100 mm2. The first material has elastic modulus E=1 GPa. The second material is twice as stiff, with a modulus of 2E or 2 GPa. The bar is subjected to an unknown distributed load fx(x), and to an unknown concentrated load F at an unknown position along the bar. As a result of these loading conditions, the displacement field of the bar is:
ux(x)={−aLx,2a(x2−Lx),if 0≤x<L/2if L/2<x≤L
where a= 0.01 [1/m] is a dimensional constant.
ux(x)={−aLx,2a(x2−Lx),if 0≤x<L/2if L/2<x≤L
where a= 0.01 [1/m] is a dimensional constant.
Answers
Answered by
access
u1 = -a*L*x1;
u2 = 2*a*(x2.^2-L*x2);
u2 = 2*a*(x2.^2-L*x2);
Answered by
access
N1 = -3*a*L*A*E+0*x1;
N2 = 6*a*A*E*(2*x2-L);
N2 = 6*a*A*E*(2*x2-L);
Answered by
access
fx1 = 0 + 0*x1;
fx2 = -12*a*A*E + 0*x2;
fx2 = -12*a*A*E + 0*x2;
Answered by
access
Fx = -3*a*L*A*E
x = L/2
x = L/2
Answered by
access
Rx(B) = 3*a*A*E*L
Rx(C) = 6*a*A*E*L
Rx(C) = 6*a*A*E*L
Answered by
FLu
Thanks Access!
Do you have HW3_2A and 2B?
Do you have HW3_2A and 2B?
Answered by
Anonymous
thanks a lot access!
Answered by
Pa
HW3_2A
N(x)= (2*p_0*L)/27-p_0*(L/3-x+(3*x^2)/(4*L))
N(x)=(2*p_0*L)/27
N(x)= (2*p_0*L)/27-p_0*(L/3-x+(3*x^2)/(4*L))
N(x)=(2*p_0*L)/27
Answered by
Pa
HW3_2B
0<x<(2/3)L
(2*p_0*L*x)/(27*E*A)-p_0/(E*A)*((L*x)/3-x^2/2+x^3/(4*L))
0<x<(2/3)L
(2*p_0*L*x)/(27*E*A)-p_0/(E*A)*((L*x)/3-x^2/2+x^3/(4*L))
Answered by
FLu
Many thanks Pa!
Answered by
Mag
THanks!
The second for HW3_2B please?
The second for HW3_2B please?
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