Asked by JD
You need to produce a solenoid that has an inductance of 2.51 μH . You construct the solenoid by uniformly winding 1.17 m of thin wire around a tube. How long, in centimeters, should the tube be?
Answers
Answered by
Elena
L=2.51•10⁻⁶ H
x=1.17 m
z=?
L=μ₀N²A/z
N=x/2πr => r= x/2πN =>
A=πr²=πx²/4π²N²
L=μ₀N²A/z= μ₀N²πx²/4π²N²z=
= μ₀x²/4z
z= μ₀x²/4L= 4π•10⁻⁷/4•2.51•10⁻⁶=0.12 m
x=1.17 m
z=?
L=μ₀N²A/z
N=x/2πr => r= x/2πN =>
A=πr²=πx²/4π²N²
L=μ₀N²A/z= μ₀N²πx²/4π²N²z=
= μ₀x²/4z
z= μ₀x²/4L= 4π•10⁻⁷/4•2.51•10⁻⁶=0.12 m
Answered by
JD
Thanks Elena. I was really stuck on the N=x/2πr. I didn't know that was a property.
But I believe there is an error in the math
z should be z= μ₀x²/4πL = .054 m
Thanks again
But I believe there is an error in the math
z should be z= μ₀x²/4πL = .054 m
Thanks again
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