Asked by Raven
A solenoid 10 turns per cm carries a current of 5A flowing through it. What is the magnetic field inside the solenoid?
Answers
Answered by
Damon
B = uo n i
uo = 4 pi * 10^-7
n = 1000 turns/meter
i = 5 amps
uo = 4 pi * 10^-7
n = 1000 turns/meter
i = 5 amps
Answered by
Belaynesh
Amare
Answered by
Jemila Ali Edris
A solenoid 10 turns per cm carries a current of 5A flowing through it.the magnetic field inside the solenoid?
Answered by
BAKHTAWAR SAMAR
100 mT
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