Asked by jenish
A 550 turn solenoid is 15 cm long. The current in it is 33 A. A 3.0 cm long straight wire cuts through the center of the solenoid, along a diameter. This wire carries a 22 A current downward( and is connected by other wires that don't concern us). What is the force on this wire assuming the solenoid's field points due east?
Answers
Answered by
drwls
Use the formula
F = B I' L
The direction will be that of I X B (south in this case)
L = 0.03 m
I' = 22 A
B is the field in the middle of the solenoid, which you should calculate with the appropriate formula. You find it at
http://en.wikipedia.org/wiki/Solenoid
It will be proportional to the solenoid current, I=22 A
F = B I' L
The direction will be that of I X B (south in this case)
L = 0.03 m
I' = 22 A
B is the field in the middle of the solenoid, which you should calculate with the appropriate formula. You find it at
http://en.wikipedia.org/wiki/Solenoid
It will be proportional to the solenoid current, I=22 A
Answered by
Zel
.10035N south
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