Asked by christiam
A 380 turn solenoid of length 32.0 cm and radius 3.10 cm carries a current of 4.80 A. Find the following.
(a) the magnetic field strength inside the coil at its midpoint
mT
(b) the magnetic flux through a circular cross-sectional area of the solenoid at its midpoint
T · m2
(a) the magnetic field strength inside the coil at its midpoint
mT
(b) the magnetic flux through a circular cross-sectional area of the solenoid at its midpoint
T · m2
Answers
Answered by
Elizabeth
(4pi*10^-7)(4.8*380/.32)
=____mT
=____mT