Asked by Anonymous
a bullet of mass 0.015kg strikes a ballistic pendullum of mass 2kg.the centre of mass of the pendulum rises a verticle distance of 0.12m.assuming that the bullet remains embedded in the pendulum, calculate the bullets initial speed.(show all calculations and steps)
Answers
Answered by
Elena
mv=(m+M)u
u =mv/(m+M),
(m+M)u²/2=(m+M)gh.
u=sqrt(2gh).
mv/(m+M)= sqrt(2gh)
v= (m+M)•sqrt(2gh)/m
u =mv/(m+M),
(m+M)u²/2=(m+M)gh.
u=sqrt(2gh).
mv/(m+M)= sqrt(2gh)
v= (m+M)•sqrt(2gh)/m
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