Question
a bullet of mass 0.05 kg strikes a wooden block of mass 5 kg and becomes embedded within the block. The block and bullet then fly off at 10 m/s after the collision. What was the original velocity of the bullet if the block was initially at rest?
Answers
momentum (as usual) is conserved
.05 * v = (5 + .05) * 10
.05 * v = (5 + .05) * 10
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