Asked by kaylee
a bullet of mass 0.05 kg strikes a wooden block of mass 5 kg and becomes embedded within the block. The block and bullet then fly off at 10 m/s after the collision. What was the original velocity of the bullet if the block was initially at rest?
Answers
Answered by
Scott
momentum (as usual) is conserved
.05 * v = (5 + .05) * 10
.05 * v = (5 + .05) * 10
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.