Asked by snehal raja acharya

A bullet having a mass of 10g and moving with a speed of 1.5m/s penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both moves together. Determine their velocity
Answered by Scott
momentum is conserved

10 * 1.5 = (90 + 10) * v
Answered by Sneha
O.15m/s
Answered by Rutuja
0.15m/s
Answered by Hshd
Jsjdh
Answered by D
0.15
Answered by Madhura
I want the answer step wise...
Answered by Rohan
0.15m/s
Answered by Rohan
0.15m/s
Answered by Abdulmuqseetsanadi
Ans. Data: m, 10 g=10 x 10-3 kg, u, -1.5 m/s, m2=90 g = 90 × 10-3 kg. u, 0 m/s, v₁ = v₂ =v=?

=

By the law of conservation of momentum,

m,u,+m,u,m,v,+m₂v₂

As u₁ = 0 m/s and v₁ = v₁ =v, we have

m,u,(m, +m₂) v

..U = mu, m+m₂

10 x 10 kg x 1.5 m/s 10 x 10 kg +90 x 10 kg

110 x 1.5 100 m/s = 0.15 m/s

The speed with which the plank containing the bullet moves = 0.15 m/s
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