Asked by snehal raja acharya
A bullet having a mass of 10g and moving with a speed of 1.5m/s penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both moves together. Determine their velocity
Answers
Answered by
Scott
momentum is conserved
10 * 1.5 = (90 + 10) * v
10 * 1.5 = (90 + 10) * v
Answered by
Sneha
O.15m/s
Answered by
Rutuja
0.15m/s
Answered by
Hshd
Jsjdh
Answered by
D
0.15
Answered by
Madhura
I want the answer step wise...
Answered by
Rohan
0.15m/s
Answered by
Rohan
0.15m/s
Answered by
Abdulmuqseetsanadi
Ans. Data: m, 10 g=10 x 10-3 kg, u, -1.5 m/s, m2=90 g = 90 × 10-3 kg. u, 0 m/s, v₁ = v₂ =v=?
=
By the law of conservation of momentum,
m,u,+m,u,m,v,+m₂v₂
As u₁ = 0 m/s and v₁ = v₁ =v, we have
m,u,(m, +m₂) v
..U = mu, m+m₂
10 x 10 kg x 1.5 m/s 10 x 10 kg +90 x 10 kg
110 x 1.5 100 m/s = 0.15 m/s
The speed with which the plank containing the bullet moves = 0.15 m/s
=
By the law of conservation of momentum,
m,u,+m,u,m,v,+m₂v₂
As u₁ = 0 m/s and v₁ = v₁ =v, we have
m,u,(m, +m₂) v
..U = mu, m+m₂
10 x 10 kg x 1.5 m/s 10 x 10 kg +90 x 10 kg
110 x 1.5 100 m/s = 0.15 m/s
The speed with which the plank containing the bullet moves = 0.15 m/s
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