Question

A bullet having a mass of 10g and moving with a speed of 1.5m/s penetrates a thick wooden plank of mass 90g. The plank was initially at rest. The bullet gets embedded in the plank and both moves together. Determine their velocity

Answer 1

momentum is conserved

10 * 1.5 = (90 + 10) * v

Answer 2

O.15m/s

Answer 3

0.15m/s

Answer 4

Jsjdh

Answer 5

0.15

Answer 6

I want the answer step wise...

Answer 7

0.15m/s

Answer 8

0.15m/s

Answer 9

Ans. Data: m, 10 g=10 x 10-3 kg, u, -1.5 m/s, m2=90 g = 90 × 10-3 kg. u, 0 m/s, v₁ = v₂ =v=?

=

By the law of conservation of momentum,

m,u,+m,u,m,v,+m₂v₂

As u₁ = 0 m/s and v₁ = v₁ =v, we have

m,u,(m, +m₂) v

..U = mu, m+m₂

10 x 10 kg x 1.5 m/s 10 x 10 kg +90 x 10 kg

110 x 1.5 100 m/s = 0.15 m/s

The speed with which the plank containing the bullet moves = 0.15 m/s