Asked by Jenna

A bullet whose mass is 1.0 x 10-3 kg leaves a 5.0 kg rifle with a muzzle velocity of 1.0 x 103 m/s. It strikes a stationary block of wood whose mass is 1.0 kg and remains embedded in it. The kinetic energy of the bullet as it travels towards the wooden block is?
Answered by Henry
KE = 0.5M*V^2.

M = 1.*10^-3 kg.
V = 1.*10^3 m/s.
Solve for KE.

Answered by فيزيا
Acheetan 101m along 41m acceleration 9•5
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