1. A bullet has mass 5g. It is fired with a velocity of 50 ms-1 (g=9.8 ms-2) and strikes on a pendulum of mass 5 kg. Find out the height at which the pendulum is raised.

Answer 1

(1/2)m1(v^2)=m2gh

m1= mass of the bullet (0.005kg)
m2=mass of the pendulum + bullet (5.005kg)

h=(m1)(v^2)/(m2)(g)
h=(0.005)(50^2)/(5.005)(9.8)
h=0.255m

Answer 2

Forgot to multiply the bottom by 2, h=0.127423