Question
A spring oriented vertically is attached to a hard horizontal surface as in the figure below. The spring has a force constant of 1.64 kN/m. How much is the spring compressed when a object of mass m = 2.35 kg is placed on top of the spring and the system is at rest?
Answers
mg=kx
x=mg/k=2.35•9.8/1.64•10³=0.014 m
x=mg/k=2.35•9.8/1.64•10³=0.014 m
F=-kx
F=mg
mg=-kx
x=mg/-k
=2.30kg×9.80bm/s^2/1460N/m
=0.0154m
F=mg
mg=-kx
x=mg/-k
=2.30kg×9.80bm/s^2/1460N/m
=0.0154m
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