A vertically hanging spring has a mass of 50 N hanging from it. Under these conditions, the spring stretches 10 cm. The spring is then placed on a horizontal table and stretched 20 cm. What force is required in the second scenario?

asked by kyle

13 years ago

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1 answer

k•x1=m•g
k=m•g/x1=50/0.1=500 N/m
F= k•x2=500•0.2=100 N.

answered by Elena

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Question

A vertically hanging spring has a mass of 50 N hanging from it. Under these conditions, the spring stretches 10 cm. The spring is then placed on a horizontal table and stretched 20 cm. What force is required in the second scenario?

1 answer

k•x1=m•g
k=m•g/x1=50/0.1=500 N/m
F= k•x2=500•0.2=100 N.

Elena · Answer

k•x1=m•g k=m•g/x1=50/0.1=500 N/m F= k•x2=500•0.2=100 N.