Asked by Daddy
a spring hanging from the ceiling. The spring constant present is 200N/m. If a mass of 50 kg is attached, how far does the spring stretch?
Answers
Answered by
bobpursley
Force=kx
50kg*9.8N/kg=200N/m * x
x= 50*9.8/200 meters
50kg*9.8N/kg=200N/m * x
x= 50*9.8/200 meters
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