Question
A mass of a copper oxide weighed 10.00grams. The reaction was run and the amount of just copper obtained was 8.88grams. What is the empirical formula of the compound?
Answers
DrBob222
10 g = copper oxide
8.88 = g Cu
-------
1.12 = g oxygen
mols Cu = 8.88/atomic mass Cu
mols O = 1.12/atomic mass O
Find the ratio of the atoms to each other. I think you will find it to be Cu2O.
8.88 = g Cu
-------
1.12 = g oxygen
mols Cu = 8.88/atomic mass Cu
mols O = 1.12/atomic mass O
Find the ratio of the atoms to each other. I think you will find it to be Cu2O.