Asked by joseph oreoluwa
what mass of nitrogen(v)oxide would be obtained by heating 33.3g of lead trioxonitrate(v)
Answers
Answered by
DrBob222
You need to learn how to name compounds. I assume nitrogen oxide(v) means N2O5; however, when lead(II) nitrate is heated this is what is produced.
2Pb(NO3)2 ==> 2PbO + O2 + 4NO2
mols Pb(NO3)2 = grams/molar mass = estimated 0.1
For every 2 mols Pb(NO3)2 you get 4 mol NO2 so for estd 0.1 mol Pb(NO3)2 you get estd 0.2 mol NO2.
Then mass NO2 = mols NO2 x molar mass NO2.
Also, there are several names for Pb(NO3)2 but lead trioxonitrate(v) is not one of them.
2Pb(NO3)2 ==> 2PbO + O2 + 4NO2
mols Pb(NO3)2 = grams/molar mass = estimated 0.1
For every 2 mols Pb(NO3)2 you get 4 mol NO2 so for estd 0.1 mol Pb(NO3)2 you get estd 0.2 mol NO2.
Then mass NO2 = mols NO2 x molar mass NO2.
Also, there are several names for Pb(NO3)2 but lead trioxonitrate(v) is not one of them.
Answered by
Ahmad
Yes
Answered by
Joshua uguru
I need the final answer
Answered by
Gold
I need the final answer for this question
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