Question

A mixture of He Ne and 3rd gas exhibit a total pressure of 486 mm hg if the partial pressure of He125mm mm hg and partial pressure of Ne is 214mm hg what is the mole fraction of the 3rd gas in container

Answer 1

XHe = pHe/total P
XNe = pNe/total P
XHe + XNe + Xunknown = 1.00
Substitute for XHe and XNe and solve for Xunknown.

Answer 2

Thanks!!!