Asked by Ray

A mixture of He Ne and 3rd gas exhibit a total pressure of 486 mm hg if the partial pressure of He125mm mm hg and partial pressure of Ne is 214mm hg what is the mole fraction of the 3rd gas in container

12 years ago

Answered by DrBob222

XHe = pHe/total P
XNe = pNe/total P
XHe + XNe + Xunknown = 1.00
Substitute for XHe and XNe and solve for Xunknown.

12 years ago

Answered by Ray

Thanks!!!

12 years ago

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