Asked by Sean
Use logarithmic differentiation to find the derivative of the following:
y=x^x^2 x>0
Please show all steps so I can following for future understanding
y=x^x^2 x>0
Please show all steps so I can following for future understanding
Answers
Answered by
Reiny
take ln of both sides
lny = ln ( x^(x^2) )
= x^2 lnx
y' /y = x^2 (1/x) + 2x lnx
y' = y (x + 2x lnx)
= xy(1 + lnx)
lny = ln ( x^(x^2) )
= x^2 lnx
y' /y = x^2 (1/x) + 2x lnx
y' = y (x + 2x lnx)
= xy(1 + lnx)
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