Asked by anonymous
Use logarithmic differentiation to find the following derivative:
y=(x+6)^4/(x-5)^6. Please show all step so I can understand for future reference.
y=(x+6)^4/(x-5)^6. Please show all step so I can understand for future reference.
Answers
Answered by
Reiny
ln y = ln(x+6)^4 - ln(x-5)^6
ln y = 4ln(x+6) - 6ln(x-5)
y' / y = 4/(x+6) - 6/(x-5)
y' or dy/dx = y(4/(x+6) - 6/(x-5))
or
(x+6)^4/(x-5)^6 (4/(x+6) - 6/(x-5) )
ln y = 4ln(x+6) - 6ln(x-5)
y' / y = 4/(x+6) - 6/(x-5)
y' or dy/dx = y(4/(x+6) - 6/(x-5))
or
(x+6)^4/(x-5)^6 (4/(x+6) - 6/(x-5) )
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