Asked by guerra

(2c+1)(3c+5)





x^2-3x-10
Answered by rbowh
What is your question?
Answered by guerra
that i don't undestand how you multiply and factor these things.
Answered by rbowh
(2c + 1)(3c + 5)
2c * 3c + 2c * 5 + 1 * 3c + 1 * 5

can you finish this?
Answered by rbowh
x^2 - 3x - 10
(x - 5)(x + 2)
Answered by guerra
(2c + 1)(3c + 5) =

6c^2+10c+3c+5
6c^2+13c+5

idk how to do this one

factor: 2x^2-7x-15
(x-4)(x+2)
Answered by rbowh
Your answer to the first one is correct.
Answered by rbowh
your answer to 2x^2 -7x - 15 is not correct because if you multiply your factors, you get
x^2 - 2x - 8
Answered by rbowh
(2x + 3)(x - 5)
Answered by guerra
i don't undertand how you got that how did you get 2 and 8 and then get 3 and 5
Answered by rbowh
You factored the expression 2x^2 - 7x - 15 and got (x - 4)(x + 2)

If you multiply those together, you do not get the original expression. Your answer is not correct.

the factors that have 3 and 5 in them are the correct answer.
Answered by guerra
oh i get thank you
Answered by Pat
You're welcome.
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