Asked by Pam
Horizontal asymptote for f(x)=10x/5x^2+1
Answers
Answered by
bobpursley
Using calculus, df/dx=10/(5x^2+1)-20x/(5x^2+1)^3(10x)=0
10=2/(5x^2+1)
25x^2+5=1
x^2=-4/25
x has no real solutions
10=2/(5x^2+1)
25x^2+5=1
x^2=-4/25
x has no real solutions
Answered by
Pam
Thank you for the help.
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