Question

Find the horizontal asymptote of the graph of y = start fraction negative 4 x superscript 6 baseline plus 6 x plus 3 over 8 x superscript 6 baseline plus 9 x plus 3 end fraction.
A. y = 1
B. y = –one-half
C. y = 0
D. There is no horizontal asymptote.

Answer 1

Learn how to type math, okay?
y = (-4x^6 + 6x + 3)/(8x^6 + 9x + 3)
then proceed as outlined by the BOT.

Answer 2

To find the horizontal asymptote, we need to look at the highest degree terms in the numerator and the denominator. In this case, both the numerator and the denominator have a term of x^6. So, as x approaches infinity or negative infinity, these terms will dominate and the function will behave like:

y = (-4x^6)/(8x^6) = -1/2

Therefore, the horizontal asymptote is y = -1/2, option B.

Answer 3

Sure, here's how to type it:

y = (-4x^6 + 6x + 3)/(8x^6 + 9x + 3)

To type exponents, use the caret (^) symbol followed by the exponent. For example, x squared would be x^2. To type fractions, use parentheses around the numerator and denominator separated by a forward slash (/).