Asked by azmeena
find the horizontal asymptote of f(x)= 8x/2x^2+1
Answers
Answered by
Steve
as x gets huge, all but the highest powers don't matter, so you have
f(x) -> 8x/2x^2 = 4/x -> 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.
f(x) -> 8x/2x^2 = 4/x -> 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.