Asked by azmeena
find the horizontal asymptote of f(x)= 8x/2x^2+1
Answers
Answered by
Steve
as x gets huge, all but the highest powers don't matter, so you have
f(x) -> 8x/2x^2 = 4/x -> 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.
f(x) -> 8x/2x^2 = 4/x -> 0
whenever the denominator is a higher power than the numerator, the asymptote is y=0.
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