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Find the horizontal asymptote of the graph of the function. (If an answer does not exist, enter DNE.)

f(x) = 5x^2 + 1/
7x^3 − 2x^2 + 5

1 answer

here the fraction approaches 5x^2/7x^3 = 5/7x -> 0

If the denominator has higher degree than the numerator, the horizontal asymptote is always y=0.
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