Question
Answer the following quadratic function
f(x)= x^2 + 6x - 16
a)What is the vertex (h,k)of f?
b)What is the axis of symmetry?
c)What are the intercepts?
f(x)= x^2 + 6x - 16
a)What is the vertex (h,k)of f?
b)What is the axis of symmetry?
c)What are the intercepts?
Answers
Steve
x^2 + 6x - 16 = (x+3)^2 - 25 = (x+8)(x-2)
that should get you started.
that should get you started.
Joe
2,-8 is your answer