Asked by Kelly
I see that this is a quadratic equaion and it has been a while sense I have taken algebra 1.... I don\'t know how to solve for t3...
-2^-1 t3^2 - 180 s t3 + t3^2 = a^-1 (Vo (180 s) - 1,100 m + Xo)
how do I solve this for t3
the 3 is a subscript to t
180 s is 180 seconds and is considered one term
Vo is one term
Xo is one term
- 1,100 m is one term and is - 1, 100 meters
-2^-1 t3^2 - 180 s t3 + t3^2 = a^-1 (Vo (180 s) - 1,100 m + Xo)
how do I solve this for t3
the 3 is a subscript to t
180 s is 180 seconds and is considered one term
Vo is one term
Xo is one term
- 1,100 m is one term and is - 1, 100 meters
Answers
Answered by
Kelly
by the way i realized i could just graph the two equations...
were
a = .20
Vo = 5.494
but how do I write it for t3
were
a = .20
Vo = 5.494
but how do I write it for t3
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