Asked by Dolores Ramirez
A solution is made by dissolving 0.10 mole of Na2SO4 in water to a final volume of 1.00 L. What is the molar concentration of Na+ ions in the solution?
Answers
Answered by
Pretender
Conc=n/v
c=0.1mol/1L
C=0.1mol/l
concentration with respect to ion=stoichiometric value*conc of solution
Na2SO4--->2Na^+1 + SO4^-2
hence conc of Na^+1=2*0.1mol/l
=0.2mol/litre
c=0.1mol/1L
C=0.1mol/l
concentration with respect to ion=stoichiometric value*conc of solution
Na2SO4--->2Na^+1 + SO4^-2
hence conc of Na^+1=2*0.1mol/l
=0.2mol/litre
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