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A plastic ball fallen 2m onto a hard floor and bounces to a height of 1.8m. Find:-{1}coefficient of restitution of the collision
1. 1 answer
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A plastic ball fallen 2m onto a hard floor and bounces to a height of 1.8m. Find:-{1}coefficient of restitution of the collision
1. 1 answer
2. 513 views
When a man in a cage whose weight is 1000N pulls a rope that is attached on a cage around a fixed pulley,the force he exerts on
1. 5 answers
2. 1,081 views

Conc=n/v c=0.1mol/1L C=0.1mol/l concentration with respect to ion=stoichiometric value*conc of solution Na2SO4--->2Na^+1 + SO4^-2 hence conc of Na^+1=2*0.1mol/l =0.2mol/litre
Quantitatively molarity=moles/dm^3 but 1dm^3=1000ml thus 1mol=>1000ml ?mol=>2ml by crossmultiplication we got 0.002mol
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Picture it like this:the rope is attached on top of the cage then from there it passes around a fixed pulley so the man in the cage is pulling the rope down from the pulley.PLEASE HELP ME Bobpursley
I think our fellow use to simplify the arithmetics coz 40/5=8 so nothing was changed.then lets solve it correctly 8-2x =1 1/5 to get 6/5 u take denominator times the whole number plus the numerator(5*1)+1 the answer will be written over the as the new

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