Asked by volek
A solution is made by dissolving 27.8 g of nicotine (Molar Mass = 160 g/mol) in 145 g of cyclohexane (C6H12) to form 142 mL of solution. Calculate the mole fraction of the solute and the molarity, respectively, of this solution.
Answers
Answered by
DrBob222
mols nicotine = grams/molar mass = ?
mols C6H12 = grams/molar mass
Find total mols.
XC6H12 = nC6H12/total mols.
M C6H12 = mols C6H12/L solution = ?
mols C6H12 = grams/molar mass
Find total mols.
XC6H12 = nC6H12/total mols.
M C6H12 = mols C6H12/L solution = ?
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