responded below.
mass % should be 2.5%. M and m are right.
whats wrong
25 g NaCl 1.0 L solution
1.0 g/mL
25 g NaCl/58.44 g NaCl= .428 mol
25g/58.44g x100= 42.8% mass percent
1000g solvent (H20)
molarity- .428 mol/1.0 L= .428 M
molality- .428 mol/1 kg= .428 molal
whats wrong? idk
mass % should be 2.5%. M and m are right.
To calculate the mole fraction of NaCl, you need to know the moles of the solvent (water) as well. Since the density of the solution is 1.0 g/mL and you have 1.0 L of solution, the mass of the solution is 1000 g (1.0 g/mL * 1000 mL = 1000 g).
To find the moles of water, you can use the molar mass of water, which is 18.015 g/mol. Divide the mass of the water by its molar mass:
1000 g water / 18.015 g/mol = 55.49 mol water
Now, to calculate the mole fraction of NaCl (X_NaCl), you can use the following formula:
X_NaCl = moles of NaCl / (moles of NaCl + moles of water)
X_NaCl = 0.428 mol NaCl / (0.428 mol NaCl + 55.49 mol water)
Simplifying this equation will give you the mole fraction of NaCl.
I hope this explanation helps! Let me know if you have any additional questions.