Asked by Jim
Algebraic factorization
1) (x+3)^2 - (x+1)^2
2) (x-4)^2-16(x+2)^2
3) 4(x+1)^2 -(2-x)^2
1) (x+3)^2 - (x+1)^2
2) (x-4)^2-16(x+2)^2
3) 4(x+1)^2 -(2-x)^2
Answers
Answered by
mani
all these can be solved by using the formula
a^2-b^2=(a+b)*(a-b)
(1)---> ans. is (2x+4)*(2)
(2)---> ans. is (5x+4)*(-3x-4)
(3)---> ans. is (3x+6)*(5x-2)
a^2-b^2=(a+b)*(a-b)
(1)---> ans. is (2x+4)*(2)
(2)---> ans. is (5x+4)*(-3x-4)
(3)---> ans. is (3x+6)*(5x-2)
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