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100 mL of is initially at room temperature (22)C. A chilled steel rod at 2 C is placed in the water. If the final temperature o...Asked by Joshua
85.0 of is initially at room temperature (22.0). A chilled steel rod at 2.0 is placed in the water. If the final temperature of the system is 21.2, what is the mass of the steel bar? Specific heat of water = 4.18 Specific heat of steel = 0.452
My answer was 32.752. I rounded it to 32.75 and it is wrong so i rounded to 32.7, then to 32.8 all in gram and Im still wrong. Please i need help. I don't know what i am doing wrong. Thanks for your help
My answer was 32.752. I rounded it to 32.75 and it is wrong so i rounded to 32.7, then to 32.8 all in gram and Im still wrong. Please i need help. I don't know what i am doing wrong. Thanks for your help
Answers
Answered by
DrBob222
85.0 what of what? And that isn't all; there are no units in the question.
Answered by
jody
A solution containing both Fe
3+
and Al
3+
can be selectively analyzed for Fe
3+
by
buffering to a pH of 2 and titrating with EDTA. Th
e pH of the solution is then raised
to 5 and an excess of EDTA added, resulting in the
formation of the Al
3+
- EDTA
complex. The excess EDTA is then back-titrated usi
ng a standard solution of Fe
3+
,
providing an indirect analysis for Al
3+
.
a.
[5 pts] Show that at a pH of 2, the formation of t
he Fe
3+
- EDTA complex is
favorable, while the formation of the Al
3+
- EDTA complex is not.
3+
and Al
3+
can be selectively analyzed for Fe
3+
by
buffering to a pH of 2 and titrating with EDTA. Th
e pH of the solution is then raised
to 5 and an excess of EDTA added, resulting in the
formation of the Al
3+
- EDTA
complex. The excess EDTA is then back-titrated usi
ng a standard solution of Fe
3+
,
providing an indirect analysis for Al
3+
.
a.
[5 pts] Show that at a pH of 2, the formation of t
he Fe
3+
- EDTA complex is
favorable, while the formation of the Al
3+
- EDTA complex is not.
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